Picc84 Posted September 20, 2006 Share Posted September 20, 2006 I was arguing with my teacher today, about something more complicated than it needed to be, but i wanted to know about the more complicated version, and she did not want to tell me, so now i need to ask someone on hear! please help me... Ok, we were working with patterns... and this was the pattern... 2,5,11,23,47,95,192,386 The Math for the pattern the easy way is... n2+1 Also there is another pattern... n3 (when "3") doubles each time... How would i write that in a mathamatical formula? such as n2+1? If you do not understand, i will try and explain more, if you need it, but please help, thank you! Link to comment Share on other sites More sharing options...
RaveN Posted September 20, 2006 Share Posted September 20, 2006 The 13 shouldn't be there. 23 I believe. The best I can give you is n+[3(2x)], Your x will go up once every time. Kind of difficult to explain, you would use words with that, I don't know the mathematical sentence for it though. Hope it helps. Link to comment Share on other sites More sharing options...
BoltBait Posted September 20, 2006 Share Posted September 20, 2006 n3 (when "3") doubles each time... Would be written: n(3^n) When you say "doubles each time" that implies an exponential function (3 to the power of n, in your example). If n=1 then you get 1(3^1)=1(3)=3 If n=2 then you get 2(3^2)=2(9)=18 If n=3 then you get 3(3^3)=3(27)= Hmmm... I don't know, I can't count that high. Is that what you were looking for? Click to play: Download: BoltBait's Plugin Pack | CodeLab | and how about a Computer Dominos Game Link to comment Share on other sites More sharing options...
Picc84 Posted September 20, 2006 Author Share Posted September 20, 2006 n3 (when "3") doubles each time...Would be written: n(3^n) When you say "doubles each time" that implies an exponential function (3 to the power of n, in your example). If n=1 then you get 1(3^1)=1(3)=3 If n=2 then you get 2(3^2)=2(9)=18 If n=3 then you get 3(3^3)=3(27)= Hmmm... I don't know, I can't count that high. Is that what you were looking for? well you cannot use the powers of 3, because you need to use odd numbers such as "6,12,18,ect..." to keep the pattern going... and 3(27)=81 i belive... Link to comment Share on other sites More sharing options...
BoltBait Posted September 20, 2006 Share Posted September 20, 2006 well you cannot use the powers of 3, because you need to use odd numbers such as "6,12,18,ect..." to keep the pattern going... Ummm... those aren't odd numbers. I'm not sure what you want then. Click to play: Download: BoltBait's Plugin Pack | CodeLab | and how about a Computer Dominos Game Link to comment Share on other sites More sharing options...
trickman Posted September 20, 2006 Share Posted September 20, 2006 boltbait is almost right I believe it is 2+(3^(n-1)) 2,5,11,23,47,95,192,386 if n=1 --> 2+(3^0) <-> 2+0 = 2 n=2 --> 2+(3^1) <-> 2+3 = 5 n=3 --> 2+(3^2) <-> 2+9 = 11 etc. I'm on the 9th grade too! Link to comment Share on other sites More sharing options...
Picc84 Posted September 20, 2006 Author Share Posted September 20, 2006 well i do not want to use the -1 method... thats why i was wondering about this... hm... lemme see, hears a better discription if its evan better? lol n+3, but "3" needs to be "6" next and "9" after that... and so on... you know? Link to comment Share on other sites More sharing options...
BoltBait Posted September 20, 2006 Share Posted September 20, 2006 Ah, yes. Now I understand what you want. Yes, trickman is on to it. I would just use * instead of x for multiplication to be less confusing. Or, just leave it out. n+3(n-1) EDIT: trickman, you made a small error... remember, that any number raised to the power of 0 = 1. Click to play: Download: BoltBait's Plugin Pack | CodeLab | and how about a Computer Dominos Game Link to comment Share on other sites More sharing options...
trickman Posted September 20, 2006 Share Posted September 20, 2006 well i do not want to use the -1 method... thats why i was wondering about this...hm... lemme see, hears a better discription if its evan better? lol n+3, but "3" needs to be "6" next and "9" after that... and so on... you know? Well I think the only way to do this is the n-1 method... Link to comment Share on other sites More sharing options...
trickman Posted September 20, 2006 Share Posted September 20, 2006 Ah, yes. Now I understand what you want.Yes, trickman is on to it. I would just use * instead of x for multiplication to be less confusing. Or, just leave it out. n+3(n-1) Actually it is n+3^(n-1). I corrected it. Link to comment Share on other sites More sharing options...
Picc84 Posted September 20, 2006 Author Share Posted September 20, 2006 Like i said, i do not want to use the (-1) method, thats the easier way, i wanted to use the harder way like this... n+3, but "3" needs to be "6" next and "9" after that... and so on... you know? But your right about that way! lol Link to comment Share on other sites More sharing options...
BoltBait Posted September 20, 2006 Share Posted September 20, 2006 boltbait is almost rightI believe it is 2+(3^(n-1)) 2,5,11,23,47,95,192,386 if n=1 --> 2+(3^0) 2+0 = 2 Slight problem there. Remember 3^0 = 1 (Any number raised to the power of 0 = 1.) Click to play: Download: BoltBait's Plugin Pack | CodeLab | and how about a Computer Dominos Game Link to comment Share on other sites More sharing options...
BoltBait Posted September 20, 2006 Share Posted September 20, 2006 n+3, but "3" needs to be "6" next and "9" after that... and so on... you know? In your first post you said that the 3 should "double" each time, but going from 6 to 9 is not doubling. So then, you want this pattern? n+3, where n=1 n+6, where n=2 n+9, where n=3 n+12, where n=4 n+15, where n=5 If so, your formula would be: n+3n or simply 4n Click to play: Download: BoltBait's Plugin Pack | CodeLab | and how about a Computer Dominos Game Link to comment Share on other sites More sharing options...
Picc84 Posted September 20, 2006 Author Share Posted September 20, 2006 Yep thats what i wanted! thanks BoltBait!!! Link to comment Share on other sites More sharing options...
DarkShock Posted February 19, 2008 Share Posted February 19, 2008 You think that's hard. Try graphing absolute inequality equations. I'm doing that in algebra II right now. ---- Gallery | Sig Tutorial | deviantART | Sig Videos | PhotoBucket ----D E S T I N Y Link to comment Share on other sites More sharing options...
R3VENGE Posted February 19, 2008 Share Posted February 19, 2008 damn my dads been on the internet for a while and id of awnsered this easily i did this a few months ago...yes im in year 9 too lol and we did this now were on some of the final topics psn id: R3V-fiR3 Link to comment Share on other sites More sharing options...
The_Lionhearted Posted February 19, 2008 Share Posted February 19, 2008 http://www.xkcd.com My Gallery Link to comment Share on other sites More sharing options...
david.atwell Posted February 19, 2008 Share Posted February 19, 2008 Ooh, those are my favorite. :-) The Doctor: There was a goblin, or a trickster, or a warrior... A nameless, terrible thing, soaked in the blood of a billion galaxies. The most feared being in all the cosmos. And nothing could stop it, or hold it, or reason with it. One day it would just drop out of the sky and tear down your world.Amy: But how did it end up in there?The Doctor: You know fairy tales. A good wizard tricked it.River Song: I hate good wizards in fairy tales; they always turn out to be him. Link to comment Share on other sites More sharing options...
The_Lionhearted Posted February 19, 2008 Share Posted February 19, 2008 Ooh, those are my favorite. :-) We talked about force the other day in Physical Science...and I thought of it. My Gallery Link to comment Share on other sites More sharing options...
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